C# ASP.NET使用ashx一般处理程序实现上传文件功能
原来以为文件上传是一个比较简单的功能，结果搞了一个晚上才搞定~这里主要介绍两种方法实现。
方法一：Form表单提交
html代码：
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>上传文件</title>
<script src="Scripts/jquery-1.11.3.min.js"></script>
</head>
<body>
<form action="UploadHandler.ashx" method="post" enctype="multipart/form-data">
<input id="file_upload" name="file_upload" type="file" />
<input id="btn_upload" type="submit" value="上传" />
</form>
</body>
</html>
UploadHandler.ashx代码：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
namespace WebApplication1
{
/// <summary>
/// UploadHandler 的摘要说明
/// </summary>
public class UploadHandler : IHttpHandler
{
public void ProcessRequest(HttpContext context)
{
context.Response.ContentType = "text/plain";
HttpPostedFile file = context.Request.Files["file_upload"];
string filePath = context.Server.MapPath("~/UploadFiles/") + System.IO.Path.GetFileName(file.FileName);
file.SaveAs(filePath);
context.Response.Write("上传文件成功");
}
public bool IsReusable
{
get
{
return false;
}
}
}
}
该方法虽然能够实现文件的上传，但是form表单提交之后整个页面就刷新了，如果要无刷新上传文件的话，就要使用ajax了。
方法二：jquery + ajax无刷上传
html代码：
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>上传文件</title>
<script src="Scripts/jquery-1.11.3.min.js"></script>
</head>
<body>
<input id="file_upload" name="file_upload" type="file" />
<input id="btn_upload" type="button" value="上传" />
<script>
$(document).ready(function ()
{
$('#btn_upload').bind('click', function ()
{
var formData = new FormData();
formData.append('upload_file', $('#file_upload')[0].files[0]);
$.ajax({
url: 'UploadHandler.ashx',
type: 'post',
data: formData,
contentType: false,
processData: false,
success: function (msg)
{
if (msg == "Yes")
{
alert('文件上传成功');
}
else
{
alert('文件上传失败');
}
}
})
});
});
</script>
</body>
</html>
UploadHandler.ashx代码：
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
namespace WebApplication1
{
/// <summary>
/// UploadHandler 的摘要说明
/// </summary>
public class UploadHandler : IHttpHandler
{
public void ProcessRequest(HttpContext context)
{
context.Response.ContentType = "text/plain";
if (context.Request.Files.Count > 0)
{
HttpPostedFile file = context.Request.Files["upload_file"];
string filePath = context.Server.MapPath("~/UploadFiles/") + System.IO.Path.GetFileName(file.FileName);
file.SaveAs(filePath);
context.Response.Write("Yes");
}
else
{
context.Response.Write("No");
}
}
public bool IsReusable
{
get
{
return false;
}
}
}
}
个人更推荐方法二，运行结果如下图所示：
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