C#.NET 身份证号码格式正则表达式验证

C# Code:


/// <summary>
/// 判断是否是正确的身份证格式，只支持18位
/// </summary>
/// <param name="s"></param>
/// <returns></returns>
///
public static bool IsPersonID(string str)
{
   if (str.IsNullOrEmpty() | !Regex.IsMatch(str.ToStringEx(), @"^((1[1-5])|(2[1-3])|(3[1-7])|(4[1-6])|(5[0-4])|(6[1-5])|71|(8[12])|91)\d{4}(((19|20)\d{2}(0[13-9]|1[012])(0[1-9]|[12]\d|30))|((19|20)\d{2}(0[13578]|1[02])31)|((19|20)\d{2}02(0[1-9]|1\d|2[0-8]))|((19|20)([13579][26]|[2468][048]|0[48])0229))\d{3}(\d|X|x)$"))
   return false;
   
   if (str.ToString().Length == 18)
   {
      string birthday = string.Empty;
      birthday = String.Format("{0}-{1}-{2}", str.ToString().Substring(6, 4), str.ToString().Substring(10, 2), str.ToString().Substring(12, 2));
      try
      {
         if (DateTime.Parse(birthday) > DateTime.Now)
         return false;
      }
      catch (Exception ex)
      {
         return false;
      }
      
      char[] code = str.ToString().ToArray();
      //加权因子
      int[] factor = { 7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2 };
      //校验位
      char[] parity = { '1', '0', 'X', '9', '8', '7', '6', '5', '4', '3', '2' };
      int sum = 0;
      for (int i = 0; i < 17; i )
      {
         sum = code[i].ToString().ToIntEx() * factor[i];
      }
      char last = parity[sum % 11];
      try
      {
         if (last != char.ToUpper(code[17]))
         {
            return false;
         }
      }
      catch (Exception)
      {
         if (last != code[17])
         {
            return false;
         }
      }
   }
   
   return true;
}

//来源:C/S框架网(www.csframework.com) QQ:1980854898